python - What is the Big-O performance of this algorithm and how do I solve this normally? -


hello have algorithm having trouble finding performance. 

 i=math.ceil(n**0.5)  while n % != 0:    -= 2

would o(2^n)?

i don't know trying do, current code run give error cannot divide zero many cases example n=13, if i-=1 in place of i-=2 code work fine without error every n , complexity o(n^(1\2)).


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