regex - Remove the data before the second repeated specified character in linux -


i have text file has below data:

ab-njcfnjnvne-802ac94f09314ee ab-kjncfvcnnjnwejj-e89ae688336716bb ab-pojkkvcmmmmmjhhgg-9ae6b707a18eb1d03b83c3 ab-qwertu-55c3375fb1ee8bcd8c491e24b2

i need remove data before second hyphen (-) , produce text file below output:

802ac94f09314ee e89ae688336716bb 9ae6b707a18eb1d03b83c3 55c3375fb1ee8bcd8c491e24b2

i pretty new linux , trying sed command unsuccessful attempts last couple of hours. how can desired output sed or other useful command awk?

you can use simple cut call:

$ cat myfile.txt | cut -d"-" -f3- > myoutput.txt

edit:
explanation, requested in comments: cut breaks string of text fields according given delimiter.
-d defines delimiter, - in case.
-f defines fields output. in case, want eliminate before second hyphen, or, in other words, return third field , onwards (3-).

the rest of command piping output. cating file cut, , saving result output file.


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