c++ - uniform_int_distribution using a list instead of a range of values -

i've looked documentation , examples after trying run code unable find method feed list uniform_int_distribution. not possible then?

does have suggestions on best way randomly pick item given list without using srand() or rand()?

you can generate random number in correct range using uniform_int_distribution, pick element of list using std::next, like:

#include <algorithm> #include <iostream> #include <list> #include <random>  int main() {     std::random_device rd;     std::mt19937 rng(rd());     std::list<char> lst{'a', 'b', 'c', 'd'};     std::uniform_int_distribution<std::size_t> uid(0, lst.size() - 1); // range [0, size-1]     std::size_t pos = uid(rng); // random index in list     auto elem = *std::next(lst.begin(), pos); // pick element     std::cout << elem << std::endl; // display }